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0=4x^2-0.63x
We move all terms to the left:
0-(4x^2-0.63x)=0
We add all the numbers together, and all the variables
-(4x^2-0.63x)=0
We get rid of parentheses
-4x^2+0.63x=0
a = -4; b = 0.63; c = 0;
Δ = b2-4ac
Δ = 0.632-4·(-4)·0
Δ = 0.3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.63)-\sqrt{0.3969}}{2*-4}=\frac{-0.63-\sqrt{0.3969}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.63)+\sqrt{0.3969}}{2*-4}=\frac{-0.63+\sqrt{0.3969}}{-8} $
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